Jika f(x)=a× + b,f(1)=3 dan F(2)=5
f(x) = ax + b
f(1) = 3
a + b = 3
b = 3 - a
f(2) = 5
2a + b = 5
2a + ( 3 - a ) = 5
a = 5 - 3
a = 2
b = 3 - a
b = 3 - 2
b = 1
Sehingga diperoleh nilai a = 2 dan b = 1
[answer.2.content]f(x) = ax + b
f(1) = 3
a + b = 3
b = 3 - a
f(2) = 5
2a + b = 5
2a + ( 3 - a ) = 5
a = 5 - 3
a = 2
b = 3 - a
b = 3 - 2
b = 1
Sehingga diperoleh nilai a = 2 dan b = 1
[answer.2.content]